Steps Necessary To Pass The 1z0-071 Exam from Training Expert UpdateDumps
Valid Way To Pass Oracle PL/SQL Developer Certified Associate's 1z0-071 Exam
NEW QUESTION 122
View the exhibit and examine the description of the PRODUCT_INFORMATIONtable.
Which SQL statement would retrieve from the table the number of products having LIST_PRICEas NULL?
- A. SELECT COUNT (DISTINCT list_price)
FROM product_information
WHERE list_price is NULL - B. SELECT COUNT (NVL(list_price, 0))
FROM product_information
WHERE list_price is NULL - C. SELECT COUNT (list_price)
FROM product_information
WHERE list_price i= NULL - D. SELECT COUNT (list_price)
FROM product_information
WHERE list_price is NULL
Answer: B
NEW QUESTION 123
Examine this statement:
CREATE TABTE orders
(sarial_no NUMBER UNIQUE,
order_id NUMBER PRIMARY KEY ,
order_date DATE NOT NULL,
status VARCHAR2 (10) CHECK (status IN ('CREDIT', 'CASH')),
product_id NUMBER REFERENCES products (product_id),
order_ total NUMBER);
On which two columns of the table will an index be created automatically?
- A. PRODUCT_ ID
- B. ORDER_ ID
- C. ORDER_DATE
- D. ORDER TOTAL
- E. SERIAL_NO
- F. STATUS
Answer: B,E
NEW QUESTION 124
Examine the description of the EMPLOYEES table:
Which query requires explicit data type conversion?
- A. SELECT join_date || ' ' || salary FROM employees;
- B. SELECT join_date + '20' FROM employees;
- C. SELECT salary + '120.50' FROM employees;
- D. SELECT join_date FROM employees WHERE join_date > '10-02-2018';
- E. SELECT SUBSTR(join_date, 1, 2) - 10 FROM employees;
Answer: D
NEW QUESTION 125
View the Exhibit and examine the structure of the EMP table which is not partitioned and not an index- organized table. (Choose two.)
Evaluate this SQL statement:
ALTER TABLE emp
DROP COLUMN first_name;
Which two statements are true?
- A. The drop of the FIRST_NAME column can be rolled back provided the SET UNUSED option is added to the SQL statement.
- B. The FIRST_NAME column would be dropped provided at least one column remains in the table.
- C. The FIRST_NAME column can be dropped even if it is part of a composite PRIMARY KEY provided the CASCADE option is added to the SQL statement.
- D. The FIRST_NAME column would be dropped provided it does not contain any data.
Answer: B
NEW QUESTION 126
The PRODUCT_INFORMATION table has a UNIT_PRICE column of data type NUMBER(8, 2).
Evaluate this SQL statement:
SELECT TO_CHAR(unit_price,'$9,999') FROM PRODUCT_INFORMATION;
Which two statements are true about the output?
- A. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,023.
- B. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as #####
- C. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,023.
- D. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,024.
- E. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,0236.
Answer: B,D
NEW QUESTION 127
View the exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID. You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?
- A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id = 100;
- B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id = 100;
- C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id = 100;
- D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id and AND e.manager_id = 100
Answer: B
NEW QUESTION 128
Examine thee statements which execute successfully:
CREATE USER finance IDENTIFIED BY pwfin;
CREATE USER fin manager IDENTIETED BY pwmgr;
CREATE USER fin. Clerk IDENTIFIED BY pwclerk;
GRANT CREATE SESSON 20 finance, fin clerk;
GRANT SELECT ON scott. Emp To finance WITH GRANT OPTION;
CONNECT finance/pwfin
GRANT SELECT ON scott. emp To fin_ _clerk;
Which two are true?
- A. Dropping user FINANCE will automatically revoke SELECT on SCOTT. EMP from user FIN _ CLERK
- B. Revoking SELECT on SCOTT. EMP from user FINANCE will also revoke the privilege from user FIN_ CLERK.
- C. User FINANCE is unable to grant ALL on SCOTT.ENP to FIN MANAGER.
- D. User FINANCE can grant CREATE SESSION to user FIN MANAGER.
- E. User FIN CLERK can grant SELECT on SCORT, ENP to user FIN MANAGER.
Answer: B,C
NEW QUESTION 129
Examine these statements executed in a single Oracle session:
Which three statements are true?
- A. The code for fountain penis 3.
- B. There is no row containing fountain pen.
- C. The code for penis 10.
- D. There is no row containing pen.
- E. There is no row containing pencil.
- F. The code for penis 1.
Answer: A,E,F
NEW QUESTION 130
n the customers table, the CUST_CITY column contains the value 'Paris' for the CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
- A. Abigail Pa
- B. An error message
- C. Abigail PA
- D. Abigail IS
Answer: A
NEW QUESTION 131
Examine this SQL statement:
SELECT cust_id, cus_last_name "Last Name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses, any one of which can complete the query successfully.
- A. ORDERBY 2, 1
- B. ORDER BY "CUST_NO"
- C. ORDER BY "Last Name"
- D. ORDER BY CUST_NO
- E. ORDER BY 2,cust_id
Answer: A,C,E
NEW QUESTION 132
Examine this SELECT statement and view the Exhibit to see its output:
SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS';
Which two statements are true about the output? (Choose two.)
- A. The STATUS column indicates whether the table is currently in use.
- B. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
- C. In the second column, 'c' indicates a check constraint.
- D. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
Answer: C,D
NEW QUESTION 133
Examine this SELECT statement and view the Exhibit to see its output: (Choose two.) SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output?
- A. The STATUS column indicates whether the table is currently in use.
- B. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
- C. In the second column, 'c' indicates a check constraint.
- D. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
Answer: C,D
NEW QUESTION 134
View the Exhibit and examine the structure of the ORDERS table.
You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?
- A. SELECT order_id, order_date FROM ordersWHERE order_date >ANY(SELECT order_date FROM orders WHERE customer_id = 101);
- B. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;
- C. SELECT order_id, order_date FROM ordersWHERE order_date > IN(SELECT order_date FROM orders WHERE customer_id = 101);
- D. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT order_date FROM orders WHERE customer_id = 101);
Answer: D
NEW QUESTION 135
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.
The PROD_ID column is the foreign key in the SALES tables, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true regarding the above command?
- A. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the specified columns would be passed to the new table.
- B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
- C. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
- D. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified columns would be passed to the new table.
Answer: D
NEW QUESTION 136
Examine the description of the EMP_DETAILS table given below:
Which two statements are true regarding SQL statements that can be executed on the EMP_DETAIL TABLE?
- A. You cannot add a new column to the table with LONG as the data type.
- B. You can alter the table to include the NOT NULL constraint on the EMP_IMAGE column.
- C. An EMP_IMAGE column can be included in the GROUP BY clause.
- D. An EMP_IMAGE column cannot be included in the ORDER BY clause.
Answer: A,D
NEW QUESTION 137
View the Exhibit and examine the structure of the BOOKStable.
The BOOKS table contains details of 100 books.
Examine the commands executed and their outcome:
Which statement is true?
- A. The first rollback restores the 100 rows that were deleted and the second rollback commits only the changes.
- B. Both ROLLBACKcommands restore the 101 rows that were deleted.
- C. The first rollback restores the 101 rows that were deleted and the second rollback causes the row was inserted to be deleted and commits the changes.
- D. Both ROLLBACKcommands restore the 100 rows that were deleted.
Answer: C
Explanation:
Explanation
NEW QUESTION 138
Sales data of a company is stored in two tables, SALES1and SALES2, with some data being duplicated across the tables. You want to display the results from the SALES1table, which are not present in the SALES2table.
Which set operator generates the required output?
- A. SUBTRACT
- B. UNION
- C. MINUS
- D. INTERSECT
- E. PLUS
Answer: C
Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/queries004.htm
NEW QUESTION 139
You execute this command:
TRUNCATE TABLE dept;
Which two are true?
- A. It always retains the space used by the removed rows.
- B. It retains the integrity constraints defined on the table.
- C. A ROLLBACK statement can be used to retrieve the deleted data.
- D. It drops any triggers defined on the table.
- E. It retains the indexes defined on the table.
- F. A FLASHBACK TABLE statement can be used to retrieve the deleted data.
Answer: B,E
NEW QUESTION 140
Which statements are true? (Choose all that apply.)
- A. Both USER_OBJECTS and CAT views provide the same information about all the objects that are owned by the user.
- B. Views with the same name but different prefixes, such as DBA, ALL and USER, use the same base tables from the data dictionary
- C. The USER_CONS_COLUMNS view should be queried to find the names of the columns to which a constraint applies.
- D. The data dictionary is created and maintained by the database administrator.
- E. The data dictionary views can consist of joins of dictionary base tables and user-defined tables.
- F. The usernames of all the users including the database administrators are stored in the data dictionary.
Answer: B,C,F
NEW QUESTION 141
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