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NEW QUESTION # 186
Which two statements are true? (Choose two.)
- A. DICTIONARY is a view that contains the names of all the data dictionary views that the user can access.
- B. All the dynamic performance views prefixed with v$ are accessible to all the database users.
- C. The USER_SYNONYMS view can provide information about private synonyms.
- D. The user SYSTEM owns all the base tables and user-accessible views of the data dictionary.
- E. The USER_OBJECTS view can provide information about the tables and views created by the user who queries the view.
Answer: C,E
NEW QUESTION # 187
View the exhibit and examine the structure in ORDERSand ORDER_ITEMStables.
You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATEVIEWstatement would create the views successfully?
CREATE OR REPLACE VIEW ord_vu
- A. AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;
CREATE OR REPLACE VIEW ord_vu - B. AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;
CREATE OR REPLACE VIEW ord_vu (order_id, order_date) - C. AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id) ||
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date
WHITH CHECK OPTION; - D. AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;
CREATE OR REPLACE VIEW ord_vu
Answer: A
NEW QUESTION # 188
Which two statements are true about selecting related rows from two tables based on entity relationship diagram (ERD)?
- A. Implementing a relationship between two tables might require joining additional tables.
- B. Every relationship between the two tables must be implemented in a Join condition.
- C. Rows from unrelated tables cannot be joined.
- D. Relating data from a table with data from the same table is implemented with a self join.
- E. An inner join relates rows within the same table.
Answer: A,D
NEW QUESTION # 189
View the Exhibit and examine the structure of the ORDERS table.
Which UPDATE statement is valid?
- A. UPDATE ordersSET order_date = '12-mar-2007',AND order_total
TO_NUMBER(NULL)WHERE order_id = 2455; - B. UPDATE ordersSET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),SET order_total = TO_NUMBER (NULL)WHERE order_id = 2455;
- C. UPDATE ordersSET order_date = '12-mar-2007',order_total = NULLWHERE order_id
2455; - D. UPDATE ordersSET order_date = '12-mar-2007',order_total IS NULLWHERE order_id
= 2455;
Answer: C
NEW QUESTION # 190
Examine the description of the BOOKS table:
The table has 100 rows.
Examine this sequence of statements issued in a new session;
INSERT INTO BOOKS VALUES ('ADV112' , 'Adventures of Tom Sawyer', NULL, NULL); SAVEPOINT a; DELETE from books; ROLLBACK TO SAVEPOINT a; ROLLBACK; Which two statements are true?
- A. The second ROLLBACK command does nothing.
- B. The second ROLLBACK command replays the delete.
- C. The first ROLLBACK command restores the 101 rows that were deleted and commits the inserted row.
- D. The second ROLLBACK command undoes the insert.
- E. The first ROLLBACK command restores the 101 rows that were deleted, leaving the inserted row still to be committed.
Answer: A,D
Explanation:
B: True. The second ROLLBACK command would not do anything because the first ROLLBACK TO SAVEPOINT a; already undid the delete operation, and there was no other DML operation between the first and the second ROLLBACK.
E: True. The second ROLLBACK command undoes the insert because after the first ROLLBACK TO SAVEPOINT a; there are no savepoints defined, so a subsequent ROLLBACK would undo all transactions to the beginning of the current session or last COMMIT.
The ROLLBACK command is used to undo transactions that have not yet been committed. Rolling back to a savepoint only undoes transactions up to that savepoint, and a subsequent ROLLBACK without a savepoint name will undo all uncommitted changes since the last COMMIT.
References:Oracle SQL documentation on the ROLLBACK statement provides details on how it interacts with savepoints and the effects it has on the transactions within a session.
NEW QUESTION # 191
Examine the data in the CUSTOMERS table:
You want to list all cities that have more than one customer along with the customer details.
Evaluate the following query:
Which two JOIN options can be used in the blank in the above query to give the correct output? (Choose two.)
- A. RIGHT OUTER JOIN
- B. NATURAL JOIN
- C. FULL OUTER JOIN
- D. JOIN
- E. LEFT OUTER JOIN
Answer: A,D
NEW QUESTION # 192
Examine the description of the EMPLOYEES table:
Which two queries return rows for employees whose manager works in a different department?
- A. SELECT emp.*
FROM employees emp
LEFT JOIN employees mgr
ON emp.manager_ id = mgr.employee_ id
AND emp. department id < > mgr. department_ id; - B. SELECT emp. *
FROM employees emp
WHERE manager_ id NOT IN (
SELECT mgr.employee_ id
FROM employees mgr
WHERE emp. department_ id < > mgr.department_ id
); - C. SELECT emp.*
FROM employees emp
WHERE NOT EXISTS (
SELECT NULL
FROM employees mgr
WHERE emp.manager id = mgr.employee_ id
AND emp.department_id<>mgr.department_id
); - D. SELECT emp. *
FROM employees emp
RIGHT JOIN employees mgr
ON emp.manager_ id = mgr. employee id
AND emp. department id <> mgr.department_ id
WHERE emp. employee_ id IS NOT NULL; - E. SELECT emp. *
FROM employees emp
JOIN employees mgr
ON emp. manager_ id = mgr. employee_ id
AND emp. department_ id<> mgr.department_ id;
Answer: C,E
Explanation:
To find employees whose manager works in a different department, you can use a subquery or a join that compares the DEPARTMENT_ID of the employee with the DEPARTMENT_ID of their manager.
A). This query is incorrect because the NOT IN subquery incorrectly attempts to compare EMPLOYEE_ID with MANAGER_ID, and the correlation condition inside the subquery is incorrect.
B). This query is correct. The NOT EXISTS clause correctly identifies employees whose MANAGER_ID matches the EMPLOYEE_ID of another employee (mgr) and where the DEPARTMENT_ID differs from that manager's DEPARTMENT_ID.
C). This query is incorrect because the LEFT JOIN will return all employees, and there is no WHERE clause to filter out those employees whose managers are in the same department.
D). This query is incorrect. The RIGHT JOIN does not ensure that the resulting rows are for employees whose manager works in a different department. It also returns all managers, which is not the requirement.
E). This query is correct. The JOIN ensures that the returned rows are for employees (emp) whose MANAGER_ID matches the EMPLOYEE_ID of managers (mgr), and it correctly filters to include only those employees whose DEPARTMENT_ID is different from their manager's DEPARTMENT_ID.
NEW QUESTION # 193
Examine the data in the ORD_ITEMS table:
Evaluate this query:
Which statement is true regarding the result?
- A. It returns an error because the HAVING clause should be specified after the GROUP BY clause.
- B. It displays the item nos with their average quantity where the average quantity is more than double the minimum quantity of that item in the table.
- C. It displays the item nos with their average quantity where the average quantity is more than double the overall minimum quantity of all the items in the table.
- D. It returns an error because all the aggregate functions used in the HAVING clause must be specified in the SELECT list.
Answer: B
NEW QUESTION # 194
View the exhibit and examine the description of the EMPLOYEES table. (Choose two.) You executed this SQL statement:
SELECT first_name, department_id, salary
FROM employees
ORDER BY department_id, first_name, salary desc;
Which two statements are true regarding the result?
- A. The values in the SALARY column would be returned in descending order for all employees having the same value in the DEPARTMENT_ID column.
- B. The values in the FIRST_NAME column would be returned in ascending order for all employees having the same value in the DEPARTMENT_ID column.
- C. The values in the all columns would be returned in descending order.
- D. The values in the SALARY column would be returned in descending order for all employees having the same value in the DEPARTMENT_ID and FIRST_NAME column.
- E. The values in the FIRST_NAME column would be returned in descending order for all employees having the same value in the DEPARTMENT_ID column.
Answer: B,D
NEW QUESTION # 195
View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?
- A. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date; - B. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)||'NO OF ITEMS'FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION; - C. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date; - D. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;
Answer: A
NEW QUESTION # 196
Which two statements are true regarding the WHERE and HAVING clauses in a SELECT statement? (Choose two.)
- A. The WHERE and HAVING clauses can be used in the same statement only if they are applied to different columns in the table.
- B. The WHERE clause can be used to exclude rows after dividing them into groups.
- C. The HAVING clause can be used with aggregate functions in subqueries.
- D. The WHERE clause can be used to exclude rows before dividing them into groups.
- E. The aggregate functions and columns used in the HAVING clause must be specified in the SELECT list of the query.
Answer: B,C
NEW QUESTION # 197
Which statement is true regarding the INTERSECT operator?
- A. The names of columns in all SELECT statements must be identical.
- B. Reversing the order of the intersected tables alters the result.
- C. It ignores NULLs.
- D. The number of columns and data types must be identical for all SELECT statements in the query.
INTERSECT Returns only the rows that occur in both queries' result sets, sorting them and removing duplicates.
The columns in the queries that make up a compound query can have different names, but the output result set will use the names of the columns in the first query.
Answer: D
NEW QUESTION # 198
Examine this SELECT statement and view the Exhibit to see its output:
SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output? (Choose two.)
- A. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
- B. The STATUS column indicates whether the table is currently in use.
- C. In the second column, 'c' indicates a check constraint.
- D. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
Answer: C,D
NEW QUESTION # 199
Examine the data in the PRODUCTStable:
Examine these queries:
Which queries generate the same output?
- A. 2 and 3
- B. 1 and 2
- C. 1 and 3
- D. 1, 2, and 3
Answer: C
Explanation:
Explanation/Reference: https://www.dofactory.com/sql/where-any-all (statement 2 syntax in wrong)
NEW QUESTION # 200
Examine these SQL statements that are executed in the given order:
What will be the status of the foreign key EMP_MGR_FK?
- A. It will remain disabled and can be enabled only by dropping the foreign key constraint and re-creating it.
- B. It will be enabled and deferred.
- C. It will be enabled and immediate.
- D. It will remain disabled and can be re-enabled manually.
Answer: D
NEW QUESTION # 201
View the exhibits and examine the structures of the COSTS and PROMOTIONS tables.
Evaluate the following SQL statement:
SQL> SELECT prod_id FROM costs
WHERE promo_id IN (SELECT promo_id FROM promotions
WHERE promo_cost < ALL
(SELECT MAX(promo_cost) FROM promotions
GROUP BY (promo_end_date-
promo_begin_date)));
What would be the outcome of the above SQL statement?
- A. It displays prod IDs in the promos with the highest cost in the same time interval.
- B. It displays prod IDs in the promos with the lowest cost in the same time interval.
- C. It displays prod IDs in the promos which cost less than the highest cost in the same time interval.
- D. It displays prod IDs in the promo with the lowest cost.
Answer: C
NEW QUESTION # 202
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